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PHP中对于AJAX请求乱码的处理函数

来源：http://www.7dit.com 作者：7dit 发布日期：2008-11-13 15:47:43 点击量：96

php如何直接解码javascript中的escape函数加码后的内容?
使用：
$result = uniDecode($str,'gb2312');
代码：
function uniDecode($str,$charcode="") {
  $text = preg_replace_callback("/%u[0-9A-Za-z]{4}/","toUtf8",$str);
  if (empty($charcode)) {
    return $text;
  } else {
    return mb_convert_encoding($text, $charcode, 'utf-8');
  }
}
function toUtf8($ar) {
  $c = "";
  foreach($ar as $val) {
    $val = intval(substr($val,2),16);
    if ($val < 0x7F){ // 0000-007F
      $c .= chr($val);
    } elseif ($val < 0x800) { // 0080-0800
      $c .= chr(0xC0 | ($val / 64));
      $c .= chr(0x80 | ($val % 64));
    } else { // 0800-FFFF
      $c .= chr(0xE0 | (($val / 64) / 64));
      $c .= chr(0x80 | (($val / 64) % 64));
      $c .= chr(0x80 | ($val % 64));
    }
  }
  return $c;
}
--------------------
code2:
function unescape($str) {
  $str = rawurldecode($str);
  preg_match_all("/%u.{4}|&#x.{4};|&#d+;|.+/U",$str,$r);
  $ar = $r[0];
  foreach($ar as $k=>$v) {
    if(substr($v,0,2) == "%u")
      $ar[$k] = iconv("UCS-2","GBK",pack("H4",substr($v,-4)));
    elseif(substr($v,0,3) == "&#x")
      $ar[$k] = iconv("UCS-2","GBK",pack("H4",substr($v,3,-1)));
    elseif(substr($v,0,2) == "&#") {
      $ar[$k] = iconv("UCS-2","GBK",pack("n",substr($v,2,-1)));
    }
  }
  return join("",$ar);
}

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